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An electron (mass m ) with initial velocity v=v_0 i+v_0 j is in an electric filed E=-E_0 k. If λ _0 is initial de-Broglie wavelength of electron, its…

JEE Main 2020 — Physics Modern Physics

2020mcqhard

An electron (mass mmm ) with initial velocity v⃗=v0i^+v0j^\vec{v}={v}_{0}\hat{i}+{v}_{0}\hat{j}v=v0​i^+v0​j^​ is in an electric filed E⃗=−E0k^.\vec{E}=-{E}_{0}\hat{k}.E=−E0​k^. If λ0{\lambda }_{0}λ0​ is initial de-Broglie wavelength of electron, its de-Broglie wave length at time ttt is given by:

Official previous-year question

Held on 8 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    λ021+e2E2t2m2v02\frac{{\lambda }_{0}\sqrt{2}}{\sqrt{1+\frac{{e}^{2}{E}^{2}{t}^{2}}{{m}^{2}{v}_{0}^{2}}}}1+m2v02​e2E2t2​​λ0​2​​

  2. B

    λ01+e2E2t2m2v02\frac{{\lambda }_{0}}{\sqrt{1+\frac{{e}^{2}{E}^{2}{t}^{2}}{{m}^{2}{v}_{0}^{2}}}}1+m2v02​e2E2t2​​λ0​​

  3. C

    λ01+e2E2t22m2v02\frac{{\lambda }_{0}}{\sqrt{1+\frac{{e}^{2}{E}^{2}{t}^{2}}{2{m}^{2}{v}_{0}^{2}}}}1+2m2v02​e2E2t2​​λ0​​

  4. D

    λ02+e2E2t2m2v02\frac{{\lambda }_{0}}{\sqrt{2+\frac{{e}^{2}{E}^{2}{t}^{2}}{{m}^{2}{v}_{0}^{2}}}}2+m2v02​e2E2t2​​λ0​​

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