Total Number of possible spectral lines that can be emmited when atom de-excites from state nto groundstate is C2n
∴nC2=6⇒2n(n−1)=6⇒n=4
λ1=Rz2(121−421)=1.097×107×9×(1−161)
⇒λ=10.8nm
JEE Main 2019 — Physics Modern Physics
InLi++,electron in first Bohr orbit is excited to a level by a radiation of wavelengthλ.When the ion gets de excited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of λ ?
(Given: h=6.63×10−34Js;c=3×108ms−1 )
Held on 10 Apr 2019 · Verified 6 Jul 2026.
10.8nm
9.4nm
11.4nm
12.3nm
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