From Einstein’s photoelectric equation,
K.Emax=λhc−λ0hc (here, λ0= threshold wavelength)
=2601237−3801237
=1237(380×260380−260)
=1.5eV
JEE Main 2019 — Physics Modern Physics
In a photoelectric effect experiment, the threshold wavelength of light is380nm . If the wavelength of incident light is260nm , the maximum kinetic energy of emitted electrons will be
Given E (in eV ) =λ(innm)1237
Held on 10 Apr 2019 · Verified 6 Jul 2026.
4.5eV
3.0eV
1.5eV
15.1eV
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