de-Broglie wavelength λ=ρh
=2meVh
λBλA=m×504m×2500
=2×52
=14.14
JEE Main 2019 — Physics Modern Physics
A particle A of mass m and charge q is accelerated by a potential difference of 50V. Another particle B of mass 4m and charge q is accelerated by a potential difference of 2500V. The ratio of de-Broglie wavelengths λBλA is close to:
Held on 12 Jan 2019 · Verified 6 Jul 2026.
0.07
10.00
4.47
14.14
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