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A metal plate of area 1× 10^-4 m^2 is illuminated by a radiation of intensity 16 milliW m^2 . The work function of the metal is 5eV. The energy of…

JEE Main 2019 — Physics Modern Physics

2019mcqmedium

A metal plate of area 1×10−4m21\times {10}^{-4}{m}^{2}1×10−4m2 is illuminated by a radiation of intensity 16milliWm216\frac{milliW}{{m}^{2}}16m2milliW​ . The work function of the metal is 5eV.5eV.5eV. The energy of the incident photons is 10eV10eV10eV and only 1010%10 of it produces photo electrons. The number of emitted photo electron per second and their maximum energy, respectively, will be: [1eV=1.6×10−19J][1 eV=1.6\times {10}^{-19}J][1eV=1.6×10−19J]

Official previous-year question

Held on 10 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    1014{10}^{14}1014 and 10eV10 eV10eV

  2. B

    1012{10}^{12}1012 and 5eV5 eV5eV

  3. C

    1011{10}^{11}1011 and 5eV5 eV5eV

  4. D

    1010{10}^{10}1010 and 5eV5 eV5eV

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