Momentum of each electron λ1hi^andλ2hj^
Velocity of centre of mass
Vcm=2mλ1hi^+2mλ2hj^
Velocity of 1st particle about centre of mass
Vcm=2mλ1hi^−2mλ2hj^
λcm=4λ12h2+4λ22h2h=λ12+λ222λ1λ2
JEE Main 2018 — Physics Modern Physics
Two electrons are moving with non-relativistic speeds perpendicular to each other. If corresponding de brogile wavelengths are λ1 and λ2, their de brogile wavelength in the frame of reference attached to their centre of mass is:
Held on 15 Apr 2018 · Verified 6 Jul 2026.
λCM1=λ11+λ21
λCM=λ12+λ222λ1λ2
λCM=λ1=λ2
λCM=2λ1+λ2
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