VAB=10V∴VBC=5V, the current in R1=I1=5005
⇒I1=10mA. Current in R2=I2=150010⇒I2=320mA
Current in zener diode = I1−I2=(10−320)mA=310mA
In the given circuit the current through zener diode is: JEE Main 2018 Physics, Semiconductors — question figure
JEE Main 2018 — Physics Modern Physics
2018mcqmedium
In the given circuit the current through zener diode is:
Official previous-year question
Held on 16 Apr 2018 · Verified 6 Jul 2026.
Options
- A
3.3mA
- B
2.5mA
- C
5.5mA
- D
6.7mA
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