According to question, λp=λα Using, λ=ph=mvh So, mp×vph=mα×vαh⇒vαvp=mpmα=mp4mp (∵ mass of α-particle is 4 times of mass of proton) So, vαvp=14; i.e., 4:1
JEE Main 2018 — Physics Modern Physics
If the de Broglie wavelengths associated with a proton and an α-particle are equal, then the ratio of velocities of the proton and the α-particle will be:
Held on 15 Apr 2018 · Verified 6 Jul 2026.
1:4
1:2
4:1
2:1
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