Power of reactor, P=ΔtE=ΔtΔmc2(From mass-energy equivalence equation)
Given in the problem power level =109Watt .
ΔtΔm=c2P=(3×108)2109
⇒ΔtΔm=910−7kgs−1
The mass of fuel consumed perhour=910−7×(1000g)(3600h−1)=4×10−2gh−1.
JEE Main 2017 — Physics Modern Physics
Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 109Watt . The mass of the fuel consumed perhour, in the reactor, will be:
(velocity of light, c is 3×108ms−1)
Held on 9 Apr 2017 · Verified 6 Jul 2026.
6.6×10−5g
0.96g
4×10−2g
0.8g
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