For a charge q moving in a uniform magnetic field B

fm=Rmv2
qVB=Rmv2
⇒mv2=qVBR
⇒21mv2=2qVBR
⇒Energy=2qVBR(1)
By Bohr's quantization condition,
Angular momentum L=n2πh
⇒mvR=2πnh
⇒vR=2πmnh(2)
Put (2) in (1)
⇒Energy=2qB(2πmnh)
=4πmqBnh
JEE Main 2015 — Physics Modern Physics
If one were to apply the Bohr model to a particle of mass ′m′ and charge ′q′ moving in a plane under the influence of a magnetic field 'B', the energy of the charged particle in the nth level will be:
Held on 10 Apr 2015 · Verified 6 Jul 2026.
n(πmhqB)
n(4πmhqB)
n(2πmhqB)
n(8πmhqB)
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