We know that
R=Bqmυ
∴υ=mBqr
∴KE=21mv2
=2mB2q2R2
= 0.79 eV
Now from photoelectric equation
E=ϕ+KE
∴ϕ=E−KE
=1.89−0.79
=1.1 eV
JEE Main 2014 — Physics Modern Physics
The radiation corresponding to 3→2 transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of 3×10−4T. If the radius of the largest circular path followed by these electrons is 10.0 mm, the work function of the metal is close to :
Held on 6 Apr 2014 · Verified 6 Jul 2026.
1.8 eV
1.1 eV
0.8 eV
1.6 eV
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