The magnetic field at the center of a circular loop is Bcenter=2Rμ0I=16μ T.
On the axis at distance x from center: B(x)=2(R2+x2)3/2μ0IR2.
At x=3R: B(3R)=2(R2+3R2)3/2μ0IR2=2(4R2)3/2μ0IR2=16Rμ0I.
The ratio: BcenterB(3R)=1/2R1/16R=81.
Therefore: B(3R)=81×16μ=2μ T.