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A plane electromagnetic wave is moving in free space with velocity c=3 × 10^8 ~m / s and its electric field is given as E=54 sin (k z-ω t) j ~V / m,…

JEE Main 2026 — Physics Electromagnetism

2026mcqmedium

A plane electromagnetic wave is moving in free space with velocity c=3×108 m/sc=3 \times 10^{8} \mathrm{~m} / \mathrm{s}c=3×108 m/s and its electric field is given as E⃗=54sin⁡(kz−ωt)j^ V/m\vec{E}=54 \sin (k z-\omega t) \hat{j} \mathrm{~V} / \mathrm{m}E=54sin(kz−ωt)j^​ V/m, where j^\hat{j}j^​ is the unit vector along yyy-axis. The magnetic field vector B⃗\vec{B}B of the wave is:

Official previous-year question

Held on 28 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    +1.8×10−7sin⁡(kz−ωt)i^ T+1.8 \times 10^{-7} \sin (k z-\omega t) \hat{i} \mathrm{~T}+1.8×10−7sin(kz−ωt)i^ T

  2. B

    1.4×10−7sin⁡(kz−ωt)k^ T1.4 \times 10^{-7} \sin (k z-\omega t) \hat{k} \mathrm{~T}1.4×10−7sin(kz−ωt)k^ T

  3. C

    −1.8×10−7sin⁡(kz−ωt)i^ T-1.8 \times 10^{-7} \sin (k z-\omega t) \hat{i} \mathrm{~T}−1.8×10−7sin(kz−ωt)i^ T

  4. D

    1.4×10−7sin⁡(kz−ωt)i^ T1.4 \times 10^{-7} \sin (k z-\omega t) \hat{i} \mathrm{~T}1.4×10−7sin(kz−ωt)i^ T

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