In an LR circuit, the equation for the voltage is given by Kirchhoff's loop law:
E=Ldtdi+iR
The instantaneous voltage across the ideal inductor is the induced EMF, which is given by:
VL=Ldtdi=E−iR
Given values are:
E=1.0 V
R=100Ω
For current i1=2 mA =2×10−3 A, the voltage across the inductor is:
VL1=1.0−(2×10−3×100)=1.0−0.2=0.8 V
For current i2=4 mA =4×10−3 A, the voltage across the inductor is:
VL2=1.0−(4×10−3×100)=1.0−0.4=0.6 V
The ratio of the instantaneous voltages is:
VL2VL1=0.60.8=34
Answer: 4/3
