The magnetic moment of the coil is given by M=NIA.
The torque acting on the coil is τ=MBsinθ=NIABsinθ.
Substituting the given values:
τ=125×1×(π×(0.02)2)×0.4×sin30∘
τ=125×1×4π×10−4×0.4×0.5
τ=100π×10−4
τ=100×3.14×10−4=314×10−4 N.m
Comparing with α×10−4 N.m, we get α=314.
Answer: 314