The direction of propagation of the electromagnetic wave is determined by the phase term 2πvt−λ2πx, which indicates that the wave is travelling along the +x direction (i^).
The direction of the magnetic field B is given as j^.
In an electromagnetic wave, the direction of propagation is given by the direction of the cross product E×B.
Let the direction of the electric field E be n^.
n^×j^=i^
Since (−k^)×j^=i^, the direction of the electric field must be −k^.
The amplitude of the electric field is related to the magnetic field by E0=cB0, where c is the speed of the wave.
The speed of the wave is c=vλ, where v is the frequency.
E0=vλB0
Therefore, the electric field vector is E=−vλB0sin(2πvt−λ2πx)k^.
Answer: E=−vλB0sin(2πvt−λ2πx)k^