The magnetic field at the centre of the circular loop is given by B=2Rμ0I
Substituting the given values, B=2×0.14π×10−7×2=4π×10−6 T
The magnetic energy density is u=2μ0B2
u=2×4π×10−7(4π×10−6)2=8π×10−716π2×10−12=2π×10−5 J/m3
The volume of the small cube is V=(1 mm)3=(10−3 m)3=10−9 m3
The magnetic energy stored inside the cube is U=u×V
U=2π×10−5×10−9=2π×10−14 J
Using π=3.14, we get U=2×3.14×10−14=6.28×10−14 J
Comparing with α×10−14 J, we get α=6.28
Answer: 6.28