The magnetic field B inside the solenoid is related to the magnetic intensity H by the formula:
B=μH=μ0μrH
Rearranging for H, we get:
H=μ0μrB
Substituting the given values (B=1.0 T, μr=400, and μ0=4π×10−7 T m/A):
H=4π×10−7×4001.0
H=1600π×10−71.0
H=16π×10−51
H=16π1×105 A/m
Comparing this with the given expression H=α×105, we find:
α=16π1
Answer: 16π1