For a magnetic dipole in an external field, torque is τ=mBsinθ
At 30°: 0.016=m×0.08×sin30°
0.016=m×0.08×0.5
m=0.4 A·m2
Work done from most stable (aligned, 0°) to most unstable (anti-aligned, 180°) position equals the change in potential energy:
W=U0°−U180°=−mBcos0°−(−mBcos180°)=−mB−mB=2mB
W=2×0.4×0.08=0.064 J =64×10−3 J
Therefore, α=64