A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B = 0.4sin(300t) Tesla. The normal to the plane of loop makes…
JEE Main 2026 — Physics Electromagnetism
2026mcqmedium
A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B=0.4sin(300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. The maximum induced emf produced in the loop is __________ mV.
Official previous-year question
Held on 6 Apr 2026 · Verified 6 Jul 2026.
Options
A
12
B
18
C
21
D
24
Did you get this right?
Sign in to track your attempts and accuracy.
Solution
Given:
Side of the square loop, a=2 cm =2×10−2 m
Area of the loop, A=a2=4×10−4 m2
Magnetic field, B=0.4sin(300t) T
Angle between the normal to the plane and the magnetic field, θ=60∘
The magnetic flux through the loop is given by:
Φ=B⋅A=BAcosθ
Φ=(0.4sin(300t))(4×10−4)cos(60∘)
Φ=1.6×10−4sin(300t)×21
Φ=0.8×10−4sin(300t) Wb
By Faraday's law of induction, the induced emf is:
e=−dtdΦ
e=−dtd(0.8×10−4sin(300t))
e=−0.8×10−4×300cos(300t)
e=−240×10−4cos(300t) V
e=−24×10−3cos(300t) V
The maximum induced emf is the amplitude of e:
emax=24×10−3 V =24 mV
Answer: 24
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.