From the electric field equation, amplitude:
E0=377 N/C
Average intensity of EM wave:
Iavg=2Z0E02 where Z0=μ0/ε0=377 Ω
Iavg=2×377(377)2=2×377377=21 W/m²
Given Iavg=α1 W/m², we have α1=21
Therefore, α=2
JEE Main 2026 — Physics Electromagnetism
The equation of the electric field of an electromagnetic wave propagating through free space is given by : E=377sin(6.27×103t−2.09×10−5x)N/C
The average power of the electromagnetic wave is (α1)W/m2. The value of α is ____
(Take εoμ0=377 in SI units)
Held on 23 Jan 2026 · Verified 6 Jul 2026.
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