Let the inductance of each inductor be L, so L1=L2=L3=L.
Let the total current flowing through the circuit be I. This current flows entirely through L1.
Since L2 and L3 are connected in parallel and have equal inductances, the current I divides equally between them. Therefore, the current through L2 is 2I and the current through L3 is 2I.
The magnetic energy stored in an inductor is given by U=21Li2.
The energy stored in the inductor L2 is:
Ul=21L(2I)2=81LI2
The equivalent inductance of the entire circuit is:
Leq=L1+L2+L3L2L3=L+L+LL⋅L=L+2L=23L
The total magnetic energy stored in the entire circuit is:
Ut=21LeqI2=21(23L)I2=43LI2
The ratio of the total energy to the energy stored in L2 is:
UlUt=81LI243LI2=43×8=6
Answer: 6
