The direction of propagation of an electromagnetic wave is given by the direction of E×B.
Given that the wave travels along the x-direction, the direction of propagation is i^.
The magnetic field is given as B=2×10−7j^ T, so its direction is j^.
Let the direction of the electric field be n^. We must have:
n^×j^=i^
Since (−k^)×j^=i^, the direction of the electric field is −k^.
The magnitude of the electric field is related to the magnetic field by E=cB, where c=3×108 m/s is the speed of light in free space.
E=(3×108)×(2×10−7)=60 V/m
Therefore, the electric field vector is E=−60k^ V/m.
Answer: −60k^