The current in the RC circuit at frequency ω is given by
I=R2+XC2V
where XC=ωC1 is the capacitive reactance.
When the frequency is changed to ω/4, the new reactance becomes XC′=(ω/4)C1=4XC.
The new current is given as I/3, so
3I=R2+(4XC)2V
Substituting the expression for I, we get
3R2+XC2V=R2+16XC2V
Squaring both sides, we obtain
9(R2+XC2)1=R2+16XC21
9R2+9XC2=R2+16XC2
8R2=7XC2
XC2R2=87
XCR=87
Answer: 87