
Eτ=2ε0σ=PEsinθ
=[(2×10−6)(102)][2×8.85×10−12100×10−6](21)=8.8510=1.12Nm
JEE Main 2025 — Physics Electromagnetism
Two small spherical balls of mass 10 g each with charges −2μC and 2μC, are attached to two ends of very light rigid rod of length 20 cm. The arrangement is now placed near an infinite nonconducting charge sheet with uniform charge density of 100μC/m2 such that length of rod makes an angle of 30∘ with electric field generated by charge sheet. Net torque acting on the rod is:
(Take ε0:8.85×10−12C2/Nm2)
Held on 4 Apr 2025 · Verified 6 Jul 2026.
112 Nm
1.12 Nm
2.24 Nm
11.2 Nm
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