Potential at C
VC=0.4kq1+0.5kq2
Potential at D
VD=0.4kq1+0.1kq2
ΔU=(VD−Vc)(q3)=(0.1kq2−0.5kq2)(q3)
ΔU=8kq2q3=4πε08q2q3
JEE Main 2025 — Physics Electromagnetism
Two charges q1 and q2 are separated by a distance of 30 cm. A third charge q3 initially at ' C ' as shown in the figure, is moved along the circular path of radius 40 cm from C to D. If the difference in potential energy due to movement of q3 from C to D is given by 4πϵ0q3 K, the value of K is :

Held on 7 Apr 2025 · Verified 6 Jul 2026.
8q2
6q2
8q1
6q1
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