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The magnetic field of an E.M. wave is given by overrightarrow B= ( √3 2 i+ 1 2 j ) 30 sin [ω ( t- z ) ] (S.I. Units). The corresponding electric…

JEE Main 2025 — Physics Electromagnetism

2025mcqeasy

The magnetic field of an E.M. wave is given by B→=(32i^+12j^)30sin⁡[ω(t−zc)]\overrightarrow{\mathrm{B}}=\left(\frac{\sqrt{3}}{2} \hat{i}+\frac{1}{2} \hat{j}\right) 30 \sin \left[\omega\left(\mathrm{t}-\frac{z}{\mathrm{c}}\right)\right]B=(23​​i^+21​j^​)30sin[ω(t−cz​)] (S.I. Units). The corresponding electric field in S.I. units is :

Official previous-year question

Held on 28 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    E→=(12i^−32j^)30csin⁡[ω(t−zc)]\overrightarrow{\mathrm{E}}=\left(\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}-\frac{z}{\mathrm{c}}\right)\right]E=(21​i^−23​​j^​)30csin[ω(t−cz​)]

  2. B

    E→=(34i^+14j^)30ccos⁡[ω(t−zc)]\overrightarrow{\mathrm{E}}=\left(\frac{3}{4} \hat{i}+\frac{1}{4} \hat{j}\right) 30 \mathrm{c} \cos \left[\omega\left(\mathrm{t}-\frac{z}{\mathrm{c}}\right)\right]E=(43​i^+41​j^​)30ccos[ω(t−cz​)]

  3. C

    E→=(12i^+32j^)30csin⁡[ω(t+zc)]\overrightarrow{\mathrm{E}}=\left(\frac{1}{2} \hat{i}+\frac{\sqrt{3}}{2} \hat{j}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}+\frac{z}{\mathrm{c}}\right)\right]E=(21​i^+23​​j^​)30csin[ω(t+cz​)]

  4. D

    E→=(32i^−12j^)30csin⁡[ω(t+zc)]\overrightarrow{\mathrm{E}}=\left(\frac{\sqrt{3}}{2} \hat{i}-\frac{1}{2} \hat{j}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}+\frac{z}{\mathrm{c}}\right)\right]E=(23​​i^−21​j^​)30csin[ω(t+cz​)]

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