For a uniformly charged spherical shell:
- The electric field inside the shell is zero everywhere (from Gauss's law)
- When the electric field is zero, no work is done in moving a charge
Since work - force × displacement, and force - q̧E (where E - 0), work - 0
The potential inside is constant and equal to the value at the surface
Assertion A is correct: Since the electric field is zero everywhere inside the shell, no work is done moving a charge between any two points, regardless of path.
Reason R is correct: The potential inside a uniformly charged spherical shell is indeed constant and equal to the value at the surface.
Does R explain A ? Yes, because:
Constant potential means zero electric field (since E=−FW)
Zero electric field means no force on a test charge
No force means no work done in moving the charge
Therefore, opxion (2) is correct: Both A and R are true and R is the correct explanation of A.