⇒t=Vxℓ=10610×10−2=10−7⇒ Vy=uy+ayt⇒Vy=0+meE×10−7⇒ Vy=9.1×10−311.6×10−19×9.1×10−2×10−7⇒ Vy=16×106
An electron is made to enter symmetrically between two parallel and equally but oppositely charged metal plates, each of 10 cm length. The electron emerges out of the electric field region with a horizontal component of velocity 106 m/s. If the magnitude of the electric field between the plates is 9.1 V/cm, then the vertical component of velocity of electron is (mass of electron =9.1×10−31 kg and charge of electron =1.6×10−19C )
Held on 22 Jan 2025 · Verified 6 Jul 2026.
0
1×106 m/s
16×106 m/s
16×104 m/s
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