
Let Ep=0
$\begin{aligned}
& \therefore \frac{\mathrm{kq}}{\mathrm{x}^2}=\frac{\mathrm{k} 9 \mathrm{q}}{(\mathrm{d}-\mathrm{x})^2} \
& \Rightarrow \frac{\mathrm{d}-\mathrm{x}}{\mathrm{x}}=3 \Rightarrow \mathrm{x}=\frac{\mathrm{d}}{4}
\end{aligned}$
∴ co-ordinate of P is (4d,0,0)