In parallel combination : Potential difference is same across all $\begin{aligned}
& \text { Energy }=\frac{1}{2}\left(\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}3\right) \mathrm{V}^2 \
& =\frac{1}{2}(25+30+45) \times(100)^2 \times 10^{-6}=0.5=\mathrm{E}
\end{aligned}Inseriescombination:Chargeissameonall.\begin{aligned}
& \frac{1}{\mathrm{C}{\text {equ }}}=\frac{1}{\mathrm{C}_1}+\frac{1}{\mathrm{C}2}+\frac{1}{\mathrm{C}3}=\frac{1}{25}+\frac{1}{30}+\frac{1}{45} \
& \frac{1}{\mathrm{C}{\text {equ }}}=\frac{(18+15+10)}{450}=\frac{43}{450} \Rightarrow \mathrm{C}{\text {equ }}=\frac{450}{43} \
& \text { Energy }=\frac{\mathrm{Q}^2}{2 \mathrm{C}_1}+\frac{\mathrm{Q}^2}{2 \mathrm{C}_2}+\frac{\mathrm{Q}^2}{2 \mathrm{C}_3} \
& =\frac{\mathrm{Q}^2}{2}\left[\frac{1}{\mathrm{C}1}+\frac{1}{\mathrm{C}2}+\frac{1}{\mathrm{C}3}\right] \
& \frac{\left(\mathrm{V} \times \mathrm{C}{\text {equ }}\right)^2}{2} \times \frac{1}{\mathrm{C}{\text {equ }}}=\frac{\mathrm{V}^2 \mathrm{C}{\text {equ }}}{2} \
& \frac{(100)^2}{2} \times \frac{450}{43} \times 10^{-6} \
& \Rightarrow \frac{4.5}{86}=\frac{9}{\mathrm{x}} \mathrm{E}=\frac{9}{\mathrm{x}} \times 0.5 \Rightarrow \mathrm{x}=86
\end{aligned}$