As source is connected in the process therefore, additional charge will be provided. Therefore, charge on C1=K(CV).
Since source is disconnected, so its charge will remain the same. Then, charge on C2=CV.
New capacitance in both cases will become, KC.
When they are connected in parallel charge will be equally divided so charge on one capacitor is q=(2K+1)CV.
So common potential,
V′=KCq=2KK+1V=55V.