
The resistance of a wire (R) is related to its resistivity (ρ), length(l) and cross-sectional area (A) as:
R=ρAl

As the length of wire increases, the cross-sectional area decreases. The cross-sectional area in terms of volume (V) and length (l) is
A=lV
∴R=ρVl2
Taking the volume of wire constant,
R∝l2
So if R′ is the resistance of wire after getting redrawn and R is the initial resistance of wire,
∴RR′=l2(5l)2=25⇒R′=25×R=125Ω