For the condition of equilibrium, the Coulomb force is equal to mgsinθ. Hence,
4h2kq02=(mgsinθ)⇒4h2kq02=(20×10−3)×10×21
⇒4h29×109×4×10−12=20×10−3×10×21⇒h=(1009)m=0.3m=300×10−3m
h2=(1009)⇒h=(103)m=0.3m
=300×10−3m
As shown in the figure, a configuration of two equal point charges (q_0=+2μ C) is placed on an inclined plane. Mass of each point charge is 20g.…
JEE Main 2023 — Physics Electromagnetism
2023integerhard
As shown in the figure, a configuration of two equal point charges (q0=+2μC) is placed on an inclined plane. Mass of each point charge is 20g. Assume that there is no friction between charge and plane. For the system of two point charges to be in equilibrium (at rest) the height h=x×10−3m. The value ofx is
( Take 4πϵ01=9×109Nm2C−2,g=10ms−2)
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Held on 11 Apr 2023 · Verified 6 Jul 2026.
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