The data given is
l=distance between the charges
q=charge
m=mass of the positive charge
2m=mass of negative charge
The moment of inertia of the system is
I=(m+2mm×2m)(l)2=32ml2
The angular frequency can be written as
ω=IpE...(i)
Substituting the value of moment of inertia in the equation (i) we get
ω=32ml2pE=2ml23pE
The value of the dipole moment is
p=ql
Hence, the angular frequency becomes
ω=2ml3qE
This question was given bonus by NTA as none of the options matched in the original paper.