
Magnetic field in parallel wires is given by B=2πdμ0I
At midway, distance=2d
∵22πdμ0I×2=B
⇒πμ0×d2I=B
⇒0.084×10−7×2I=300×10−6
⇒I=2×4×10−73×10−4×0.08=30A
As Bnet=0, so the wires are carrying current in opposite direction.
JEE Main 2022 — Physics Electromagnetism
Two long current carrying conductors are placed parallel to each other at a distance of 8cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300μT. The equal current flowing in the two conductors is :
Held on 29 Jun 2022 · Verified 6 Jul 2026.
30A in the same direction.
60A in the opposite direction.
30A in the opposite direction.
300A in the opposite direction.
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
A magnetic field vector in an electromagnetic wave is represented by $\vec{B}=B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{j}$. Its associated electric field vector is ______.
A plane electromagnetic wave is moving in free space with velocity $c=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ and its electric field is given as $\vec{E}=54 \sin (k z-\omega t) \hat{j} \mathrm{~V} / \mathrm{m}$, where $\hat{j}$ is the unit vector along $y$-axis. The magnetic field vector $\vec{B}$ of the wave is:
A charged particle moves in a uniform magnetic field. If the velocity is perpendicular to the field, the path of the particle is:
A monochromatic source of light operating at $15$ kW emits $2.5\times 10^{22}$ photons/s. The region of an electromagnetic spectrum to which the emitted electromagnetic radiation belongs to ________. (Take $h=6.6\times 10^{-34}$ J·s and $c=3\times 10^8$ m/s).
An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, $\sigma=10 \mathrm{mho} / \mathrm{m}$. The ratio of maximum conduction current density to maximum displacement current density is $\_\_\_\_$. $\left[\text{Take }\frac{1}{4 \pi \epsilon_{\mathrm{o}}}=9 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right]$
Work through every JEE Main Electromagnetism PYQ, year by year.