In inductive circuit, the voltage leads the current by 90∘. Therefore,
ϕ0V−ϕ0I=90∘⇒ϕ0V=60∘
From the given equation 5sin(49πt−30∘), angular frequency ω=49πrads−1
The amplitude of the voltage across the inductor will be,
V0=i0XL
⇒V0=i0(ωL)
⇒V0=(5)(49π)(30×10−3)=23.1
⇒V=23.1sin(49πt+60∘)