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Light wave travelling in air along x-direction is given by E_y=540 sinπ × 10^4(x-ct)Vm^-1. Then, the peak value of magnetic field of wave will be…

JEE Main 2022 — Physics Electromagnetism

2022mcqeasy

Light wave travelling in air along xxx-direction is given by Ey=540sinπ×104(x−ct)Vm−1{E}_{y}=540\mathrm{sin}\pi \times {10}^{4}(x-ct)V{m}^{-1}Ey​=540sinπ×104(x−ct)Vm−1. Then, the peak value of magnetic field of wave will be (Given c=3×108ms−1c=3\times {10}^{8}m{s}^{-1}c=3×108ms−1)

Official previous-year question

Held on 25 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    18×10−7T18\times {10}^{-7}T18×10−7T

  2. B

    54×10−7T54\times {10}^{-7}T54×10−7T

  3. C

    54×10−8T54\times {10}^{-8}T54×10−8T

  4. D

    18×10−8T18\times {10}^{-8}T18×10−8T

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