Given here: L=0.5×10−3H
C=200×10−6F
R=2Ω.
If current is in phase with emf, so this is the condition of resonance.
f=fR=2πLC1=2×3.14LC1
f=6.280.5×10−3×200×10−61=503.55Hz=5.03×102Hz
JEE Main 2022 — Physics Electromagnetism
An inductor of 0.5mH, a capacitor of 200μF and a resistor of 2Ω are connected in series with a 220V ac source. If the current is in phase with the emf, the frequency of ac source will be ______×102Hz.
Held on 29 Jun 2022 · Verified 6 Jul 2026.
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