Fiven that E=Ek^ and B=12j^mT
Kinetic energy=728eV
Kinetic energy =21mv2
⇒728eV=21×9.1×10−31×v2
⇒728×1.6×10−19=21×9.1×10−31×v2
⇒v=16×106ms−1
For electron to move undeflected net force on it should be zero.
⇒eE=evB
⇒E=vB=16×106×12×10−3
⇒E=192×103Vm−1=192kVm−1