Since the transformer is assumed to be purely resistive, the power of the transformer can be calculated with P=RV2. Therefore,
For the primary coil,
P=RP(8×103)2=80×103W
⇒RP=800Ω
For the secondary coil,
P=RS(160)2=80×103W
⇒RS=0.32Ω
JEE Main 2022 — Physics Electromagnetism
A transformer operating at primary voltage 8kV and secondary voltage 160V serves a load of 80kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be
Held on 28 Jul 2022 · Verified 6 Jul 2026.
800Ω and 1.06Ω
10Ω and 500Ω
800Ω and 0.32Ω
1.06Ω and 500Ω
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