For an LCR circuit. the resonant angular frequency is given by, ω0=LC1=104rads−1
The given frequency is 60 lower than resonant frequency. Therefore,
ω′=0.4×104=4000rads−1
Reactance of the capacitor at given frequency,
XC=(ω′C)−1=250Ω.
Reactance of the inductor at given frequency,
XL=(ω′L)=40Ω
Now the amplitude of the current in the given circuit will be,
i0=R2+(XC′−XL′)2V0=102+(250−40)250=238mA