Given here, BH=0.2×10−4T, ω=5rads−1 and l=1m.
Emf induced in a rotating conducting rod is given by,
ϵ=21Bωl2
Substituting the given values, we obtain
ϵ=21×0.2×10−4×5×(1)2=0.5×10−4V=50μV
JEE Main 2022 — Physics Electromagnetism
A metallic conductor of length 1m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5rads−1. If the horizontal component of earth's magnetic field is 0.2×10−4T, then emf induced between the two ends of the conductor is
Held on 26 Jun 2022 · Verified 6 Jul 2026.
5μV
50μV
5mV
50mV
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