We know that in the discharging circuit the charge is given by,
q=q0eRC−t ⇒RCt=ln(qq0)
In time t1 the energy stored reduces to half. Hence, 2Cq12=21×2Cq02⇒q1q0=2. Therefore,
RCt1=ln(2)=21ln2.
In time t2 the charge stored reduces to 81th of initial value. Hence, q0q2=81. Therefore,
RCt2=ln(8)=3ln2.
Hence,
t2t1=3ln221ln2=61