C = ε₀A/d. Energy U = ½CV² = ½ × (ε₀A/d) × V² = ε₀AV²/(2d)
JEE Main 2021 — Physics Electromagnetism
Verified 30 May 2026.
Question
A parallel plate capacitor has plate area A and separation d. It is charged to potential V. The energy stored in the capacitor is:
Options
- Aε₀AV²/(2d)
- Bε₀AV²/d
- Cε₀Ad/V²
- Dε₀A/(2dV²)
Solution
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