
We can arrange the circuit like above now on solving we get a simplified circuit,

here, both the resistance are connected in series then resultant resistance will be,
Req=34Ω+14Ω=346Ω, in the other case we can not get this result.
JEE Main 2021 — Physics Electromagnetism
If you are provided a set of resistances, 2Ω,4Ω,6Ω and 8Ω. Connect these resistances to obtain an equivalent resistance of 346Ω.
Held on 26 Aug 2021 · Verified 6 Jul 2026.
2Ω and 6Ω are in parallel with 4Ω and 8Ω in series
4Ω and 6Ω are in parallel with 2Ω and 8Ω in series
2Ω and 4Ω are in parallel with 6Ω and 8Ω in series
6Ω and 8Ω are in parallel with 2Ω and 4Ω in series
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