
4an1=24a
thus n1=6 turns

3an2=24a⇒n2=8 turns
M2M1=n2iA2n1iA1=8×a2×436×a2=13
M1M2=31=y1
y=3
A uniform conducting wire of length is 24a, and resistance R is wound up as a current carrying coil in the shape of an equilateral triangle of side a and then in the form of a square of side a. The coil is connected to a voltage source V0. The ratio of magnetic moment of the coils in case of equilateral triangle to that for square is 1:y where y is ____________.
Held on 27 Aug 2021 · Verified 6 Jul 2026.
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