
Let E be electric field in air
Tsinθ=qE
Tcosθ=mg
tanθ=mgqE

Q=[C1+C2C1C2][V1+V2]
E=AI¨μoQ=[C1+C2C1C2]AI¨μo[V1+V2]
C1=d−tI¨μ0A⇒E=(C1+C2)(d−t)C2[V1+V2]
Now θ=tan−1[mgq⋅E]
θ=tan−1[mgq×(C1+C2)(d−t)C2(V1+V2)]
A simple pendulum of mass ' m ', length ' l ' and charge ′+q′ suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be

Held on 27 Jul 2021 · Verified 6 Jul 2026.
tan−1[mgq×(C1+C2)(d−t)C1(V2−V1)]
tan−1[mgq×(C1+C2)(d−t)C2(V2−V1)]
tan−1[mgq×(C1+C2)(d−t)C2(V1+V2)]
tan−1[mgq×(C1+C2)(d−t)C1(V1+V2)]
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