Emf=BωNAsinωt
Emfmax=BωNA=BωN(πR2)
=(3×10−2)×(50)×(20)×(π×10464)≈60×10−2V
A circular coil of radius 8.0cm and 20 turns is rotated about its vertical diameter with an angular speed of 50rads−1 in a uniform horizontal magnetic field of 3.0×10−2T. The maximum emf induced in the coil will be _______×10−2 volt (rounded off to the nearest integer).
Held on 26 Aug 2021 · Verified 6 Jul 2026.
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