The magnetic field due to the current-carrying finite length wire is given by
B=4πRμ0I[sinθ1+sinθ2]
Here for hexagonal shape coil, θ1=θ2=30∘.
So, the net magnetic field at the centre will be B=50×6×4π(10010cos30∘)μ0i[sin30∘+sin30∘]
B=2×75×103πμ0i(21+21)
B=31500πμ0i=(5003)πμ0i